Math, asked by Anonymous, 24 days ago

What is the hight of a cylinderical box f radius 10 cm and total surface area 942cm square?
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Answers

Answered by 1980seemamishra
11

Answer:

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Step-by-step explanation:

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Answered by мααɴѕí
22

Step-by-step explanation:

Solution:-

we know T.S.A = 942 cm²

So,

942 = 2πr (r + h)

Radius = 10 cm

= 942 = 2 × 22/7 × 10 (10 + h)

= 942 = 440/7 (10 + h)

= 942 × 7 = 440 (10 + h)

= 6594 = 440 (10 + h)

= 6594/440 = (10 + h)

= 3297/220 = (10 + h)

= 3297/220 - 10/1 = h

= 3297 - 2200/220 = h

= 1097 / 220 = h

Height = 1097 / 220 cm (Ans)

Mark the above answer brainliest ✌️

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