What is the hight of a cylinderical box f radius 10 cm and total surface area 942cm square?
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Answered by
11
Answer:
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Step-by-step explanation:
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Answered by
22
Step-by-step explanation:
Solution:-
we know T.S.A = 942 cm²
So,
942 = 2πr (r + h)
Radius = 10 cm
= 942 = 2 × 22/7 × 10 (10 + h)
= 942 = 440/7 (10 + h)
= 942 × 7 = 440 (10 + h)
= 6594 = 440 (10 + h)
= 6594/440 = (10 + h)
= 3297/220 = (10 + h)
= 3297/220 - 10/1 = h
= 3297 - 2200/220 = h
= 1097 / 220 = h
Height = 1097 / 220 cm (Ans)
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