Question

what is the horizontal distance covered by a ball when its time of flight is 2second and velocity is 19. 6 at an angle of 30 degree with horizontal

Answer 1

Answer:

19.6(3)^1/2

Explanation:

R=Ux*t.

Ux=ucos(30)=19.6*(1/2)(3)^1/2

(19.6*(1/2)(3)^1/2)*2

=19.6(3)^1/2

answer

Answer 2

The horizontal distance coveres is nothing but Range.

We know Range

                            = u^2sin2theta/g

                            =(19.6)(19.6)2(30degrees)/9.8

                            =19.6root3

It is the required anwer.

hope so it will help you.