what is the hybridization of chlorine in methyl chloride
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Hybridisation = number of sigma bonds + lone pair. CH3Cl = 3 sigma bonds between C & H and 1 between C and Cl There is no lone pair as carbon has 4 valence electrons and all of them have formed a bond (3 with hydrogen and 1 with Cl). Now, hybridisation = (3+1) + 0= 4 = sp3 (1 s & 3 p)
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