What is the hydrolysis constant of
the ocl- ion ? The ionization
constant of Hocl is 3.0x 10-8?
Answers
Answer:
The ionization constant of HOCl is 3.0×10
−8
HOCl+H
2
O→H
3
O
+
+OCl
−
K
a
=
[HOCl]
[H
3
O
+
][OCl
−
]
=3.0×10
−8
The hydrolysis of the OCl
−
ion
OCl
−
+H
2
O→HOCl+OH
−
The hydrolysis constant of the OCl
−
ion
K
h
=
[OCl
−
]
[HOCl][OH
−
]
K
a
×K
h
=K
w
=[H
3
O
+
][OH
−
]=10
−14
3.0×10
−8
×K
h
=10
−14
K
h
=3.33×10
−7
Explanation:
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Answer:
11th
Chemistry
Equilibrium
Hydrolysis of Salts and the pH of their Solutions
What is the hydrolysis cons...
CHEMISTRY
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Asked on December 20, 2019 by
Asmita Savani
What is the hydrolysis constant of the OCl
−
ion?
Given the ionization constant of HOCl is 3.0×10
−8
HARD
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ANSWER
The ionization constant of HOCl is 3.0×10
−8
HOCl+H
2
O→H
3
O
+
+OCl
−
K
a
=
[HOCl]
[H
3
O
+
][OCl
−
]
=3.0×10
−8
The hydrolysis of the OCl
−
ion
OCl
−
+H
2
O→HOCl+OH
−
The hydrolysis constant of the OCl
−
ion
K
h
=
[OCl
−
]
[HOCl][OH
−
]
K
a
×K
h
=K
w
=[H
3
O
+
][OH
−
]=10
−14
3.0×10
−8
×K
h
=10
−14
K
h
=3.33×10
−7
Explanation:
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