What is the hypotenuse of the right triangle with
perpendicular sides √3 cm. and √2 cm ? How much larger
than the hypotenuse is the sum of the perpendicular sides?
Answers
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4
Answer:
Answer:
2.236 cm , 0.9101 cm
Step-by-step explanation:
Let ABC be a triangle.
Let BC be a hypothenuse.
AB = √2 cm = 1.414 cm
AC = √3 cm = 1.732 cm
BC^{2} =AC^{2} +AB^{2} = 2+3=5BC
2
=AC
2
+AB
2
=2+3=5
BC=\sqrt{5}=2.236cmBC=
5
=2.236cm
We now need to find AB+AC-BCAB+AC−BC
AB+AC-BC= 1.414 cm + 1.732 cm - 2.236 cmAB+AC−BC=1.414cm+1.732cm−2.236cm
= 0.9101 cm=0.9101cm
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