Math, asked by Appu4731, 2 months ago

What is the hypotenuse of the right triangle with
perpendicular sides √3 cm. and √2 cm ? How much larger
than the hypotenuse is the sum of the perpendicular sides?​

Answers

Answered by study12345677890
4

Answer:

Answer:

2.236 cm , 0.9101 cm

Step-by-step explanation:

Let ABC be a triangle.

Let BC be a hypothenuse.

AB = √2 cm = 1.414 cm

AC = √3 cm = 1.732 cm

BC^{2} =AC^{2} +AB^{2} = 2+3=5BC

2

=AC

2

+AB

2

=2+3=5

BC=\sqrt{5}=2.236cmBC=

5

=2.236cm

We now need to find AB+AC-BCAB+AC−BC

AB+AC-BC= 1.414 cm + 1.732 cm - 2.236 cmAB+AC−BC=1.414cm+1.732cm−2.236cm

= 0.9101 cm=0.9101cm

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