What is the (i) highest (ii) lowest resistance that can be secured by combination of four coils of resistance 4ohm ,8ohm ,10ohm and 20ohm
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Answer:
FOR HIGHEST RESISTANCE
R= R1 + R2 + R3 + R4
R= 4+8+12+20
R= 42 Ohm
FOR LOWEST RESISTANCE
1/R= 1/R1+1/R2+1/R3+1/R4
1/R = 1/4+1/8+1/12+1/20
1/R = 84/160
R = 1.09 ohm
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