What is the identity of(a-b) 3 ? solve (x/2-3/y) 3
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(a-b)³= a³-3a²b+3ab²-b³
(x/2-3/y)³ = (x/2)³-3*(x/2)²*3/y +3* x/2 *(3/y)²- (3/y)³
= x³/8 -9/4x²/y+27/2*x/y² - 27/y³
(x/2-3/y)³ = (x/2)³-3*(x/2)²*3/y +3* x/2 *(3/y)²- (3/y)³
= x³/8 -9/4x²/y+27/2*x/y² - 27/y³
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