Question

What is the image distence for an object distence(u)=30cm before a convex lens having 15cm focal lenth

Answer 1

Explanation:

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

focal length (f) = + 15cm

Object distance (u) = -30cm

$\frac{1}{v} = \frac{1}{f} + \frac{1}{u}$

$\frac{1}{v } = \frac{1}{15} - \frac{1}{30}$

$\frac{1}{v} = \frac{2 - 1}{30}$

$\frac{1}{v} = \frac{1}{30}$

$v = 30cm \: \: \: \: \: \: answer$