Question

What is the image of the point (1, 3) in the line x+y-6=0? Thanks!

Answer 1

THE GIVEN EQUATION OF LINE IS=> X+Y-6=0

   FORMULA FOR FINDING IMAGE OF POINT WITH RESPECT TO LINE IS~

   \frac{x-x1}{a} =\frac{y-y1}{b} =-2[\frac{ax1+by1+c}{a^{2} +b^{2}} ]

   here x1=1 and y1=3 and ( x,y) coordinates of image

   by comparing given equation with general linear equation ax+bx+c=0 we get

   a=1

   b=1

   c=-6

   x-1/1=y-3/1=-2(1*1+1*3-6)/2

   therefore x-1=2 ,x=3

   y-3=2,y=5

   image coordinates (3,5)

   hope it helps u

   jai hind