Question

*What is the imaginary part of (3 + 2i)(2 − i)?*

1️⃣ 1
2️⃣ −i
3️⃣ 8
4️⃣ 8i​

Answer 1

$(3 + 2i)(2-i)\\</p><p>\implies 3(2 - i) + 2i(2-i)\\ \implies 6 - 3i + 4i - 2i^2\\ \implies 6 + i - 2(-1) \: (i^2 = -1)\\</p><p>\implies 8 + i \\ \text{Hence the imaginary part} = 1$