what is the % increase in the area of a reactagle if its length is increased by 20%?
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Let the length be X and the breadth be Y
then
area of rectangle=l×b=XY
A.T.Q
New length=20/100X+X=6X/5
Breadth=Y
New Area=6X/5×Y=6XY/5
Percentage increase in area=(Final-Initial)/Initial ×100
Therefore,% increase=XY/5×1/XY×100=20%
Hope it helps!!
then
area of rectangle=l×b=XY
A.T.Q
New length=20/100X+X=6X/5
Breadth=Y
New Area=6X/5×Y=6XY/5
Percentage increase in area=(Final-Initial)/Initial ×100
Therefore,% increase=XY/5×1/XY×100=20%
Hope it helps!!
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