What is the increase in the entropy when 11.2L O2 and 11.2L H2 are mixed at STP
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Answered by
342
S =8.314 x 2.303 (v1 log.n1 + v2 log.n2)
=8.314 x 2.303 (0.5 log 0.5+0.5 log 0.5)
=8.314 x 2.303 (-0.3010)
=- 5.76
=8.314 x 2.303 (0.5 log 0.5+0.5 log 0.5)
=8.314 x 2.303 (-0.3010)
=- 5.76
Answered by
156
"When you add energy to the solid then it becomes a liquid.
STP is the temperature of 273.15 K (0 °C, 32 °F) which is absolute pressure based on 105 Pa (100 kPa, 1 bar).
S = 8.314 x 2.303 (v1 log.n1 + v2 log.n2)
= 8.314 x 2.303 (0.5 log 0.5+0.5 log 0.5)
= 8.314 x 2.303 (-0.3010)
=- 5.76
"
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