Question

What is the index number of the last element of an array with 29 elements?

Answer 1

The positioning of array starts from subscript 0.

Well subscript is also known as indices. It is the value in big brackets [].

To find index number, u can use the formula (n-1).

Here n=29 so (n-1)=28.

Hence the index of the 29th element is 28.

# Hope it helps.
# Smritu.

Answer 2

The index number of the last element of an array with 29 elements is 28.

• An array which is a linear type data structure is a collection of indexed data elements all of the same type.

• Indexed means that all the elements of the array from first to last are numbered, starting at 0.

• The array is indexed from 0 to n-1, where n is the number of elements present in an array.
• n-1 is there because the array is indexed starting from zero and not from one.
• With proper indexing of an array we can reference the position of each element in the array to manipulate the element's data and can also access the element of data without manually finding the elements from the large list of elements.

• If the elements of the array are 5,10,15,20,25 then, the index of 5 would be 0 and the index of 25 would be 4.

• Similarly if an array consists of 29 elements then its index would range from 0 to n-1, i.e. 0 to 28, where 0 is the index of the first element and 28 is the index of the last element.