What is the initial speed of the car.
What is the maximum speed attained by car
Which part of the graph shows zero acceleration
Which part of the graph shows varying retardation
Find the distance travelled in first eight years
Answers
Answer:
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Explanation:
(a) 10 km/h
(b) 35 km/h
(c) BC
(d) CD
(e) Distance travelled in first eight hours = Area of trapezium OABE + area of rectangle EBCF
= 1 / 2 ( 10 + 35) × 3 + 35 × 5 = 242.5 km
Answer:
The initial speed is 10km/hr, maximum speed attained is 35km/hr, B to C part of a graph shows zero acceleration, C to D part of the graph shows varying retardation and the distance travelled in first hours is 1.25 km.
Explanation:
Given
A car is in motion and the graph shows time along X-axis and speed along Y-axis.
The letters A,B, C and D shows different position of car.
a. To find the initial speed of the car
Solution:
The car starts from 'A'.
Thus, the initial speed of a car is 10km/hr.
b. To find the maximum speed attained by car
Solution:
The maximum speed of a car is shown at position B to C.
Hence, the maximum speed is 35 km/hr.
c. To show part of the graph showing zero acceleration
Solution:
The car is at uniform velocity on moving from B to C.
Initial velocity of a car (u)=35km/hr
Final velocity of a car (v)=35km/hr
time taken (t)=5 hr
Acceleration (a)=?
Using formula
a=v-u/t
a=35-35/5
a=0
Hence, part of the graph showing zero acceleration is B to C.
d. To show part of the graph shows varying retardation
Solution:
The velocity from C to D is non-uniform.
u=35 km/hr
v=0 km/hr
t=2 hr
Using formula
a=v-u/t
a=0-35/2
a= - 17.5
Retardation= -a
= -(-17.5)
=17.5km/hr^2
Hence, the retardation is 17.5km/hr^2 and it is shown at C to D part of graph.
e. To find the distance travelled in first eight hours
Solution:
u=10 km/hr
v=0 km/hr
t=8 hr
distance travelled (s)=?
Using the formula
s= v-u/t
=0-10/8
=1.25 km
Hence, the distance travelled in first 8 hours is 1.25 km.