What is the instantaneous rate of change of the area of a circle when the radius is 3cm?
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A=πr2
Differentiating with respect to r we get the rate of change of A with respect to r as function of r
A(r)=dAdr=2πr
So the rate of change in the area of a circle when the radius is 3cm will be
A(3)=[dAdr]r=3=2π×3=6π cm
Differentiating with respect to r we get the rate of change of A with respect to r as function of r
A(r)=dAdr=2πr
So the rate of change in the area of a circle when the radius is 3cm will be
A(3)=[dAdr]r=3=2π×3=6π cm
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MARK BRAINLIEST..
MARK BRAINLIEST..
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