Question

what is the integral for ∫√ x^ 2 - x ^4 dx

Answer 1

Answer:

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Answer 2

Step-by-step explanation

∫√ x^ 2 - x ^4 dx

=∫$(x^{2} -x^{4})^{1/2}dx$

=$\frac{(x^{2} -x^{4})^{3/2}}{3/2}$*∫$(x^{2} -x^{4})dx$

=$\frac{(x^{2} -x^{4})^{3/2}}{3/2}*(\frac{x^{3}}{3} -\frac{x^{5}}{5} )+c$