what is the integral of 1/(x+2)
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Hi Mate!!!
The given question can be written like this.
( x + 2 )^ ( -2 ) dx
itz Integration is
-1 / ( x + 2 ) + c where c is called constant
of integration
The given question can be written like this.
( x + 2 )^ ( -2 ) dx
itz Integration is
-1 / ( x + 2 ) + c where c is called constant
of integration
simonsays911xxx:
would it not be ln(x+2)
Was it 1 ( x + 2 ) dx. or 1 / ( x + 2 ) × 1 / ( x + 2 ) dx
no. it was 1 upon x plus 2
Then its integration is Log ( x + 2 ) +c
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