What is the integral of (3t - 1)3 dt?
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Step-by-step explanation:
The answer is t³/3 + 3t⁴/4 + C
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Step 1
We first find the slope of the tangent for which we need derivative of f(x).
f'(x)=d/dx (3x^3+3x^2+x+1)
=3d/dx (x^3)+2d/dx (x^2)+d/dx (x)+d/dx(1)
=3*3x^2+2*2x+1+0
=9x^2+4x+1
Step 2
Now, slope is the value of f’(x) at the given point x = 1.
slope = f'(x)|x = 1 = f'(1) = 9+4+1 = 14
Step 3
Now, to find any one point on the tangent line, we consider the fact that tangent line is drawn at x=1.
f (x)|x = 1= f (1) =:3+2+1+1 = 7
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