What is the integral of (√x+1/ Vx)
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Answered by
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continue:
x + x^(½)/1/2 + c
x + 2√x + c = I is Answer
First refer attachment, then this text.
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Answered by
147
Step-by-step explanation:
Given :
- What is the integral of (√x+1/ Vx)
To Find :
- Find the integers
Solution :
Concept :
- The number line goes on forever in both directions. Whole numbers greater than zero are called positive integers. Whole numbers less than zero are called negative integers.
The integer zero is neutral.
- The sign of an integer is either positive or negative,except for zero which has no sign.
= (√x+1/ Vx)
= (√x+1/ x) × √x / √x × dx
= ( 1 + √x / x )× dx
= ( 1 + x ½ -¹ ) dx
= x + ( x -½ +¹ /-½ +¹ ) + c
= x + x^ /½ + c
= x + 2√x + c = I
First refer attachment, then this text.
Hence the integers is x + 2√x + c = I
Anonymous:
Great!
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