Question

what is the integration of 0 to pi by 4 tan square theta d theta how to solve this problem​

Answer 1

Answer:

1-pi/4

or

(4-pi)/4

Step-by-step explanation:

we know that sec²x-tan²x=1

tan²x= sec²x-1

and integral of sec²xdx = tanx + C

and integral of 1dx = x+ C

using the formula of integration

integral x^ndx ={ x^(n+1)}/(n+1) + C