Question

What is the integration of a negative number or constant?
for example- integration of ( -2 dx )​

Answer 1

Answer:

integral can be negative. Integrals measure the area between the x-axis and the curve in question over a specified interval. ... If ALL of the area within the interval exists below the x-axis yet above the curve then the result is negative .

Answer 2

Here is Your answer ❤

∫dx=−10∫1+20v−20dvx

=−10(v+20ln|v−20|)+Cx+C

=−10(v+20ln|v−20|)

Since

x+D

=−10(v+20ln|v−20|)+E and D−E is an unknown constant, and so is E−D.

Anyways, then it's given that when x=0, v=0 so we substitute those in to get the value of the constant.So if you try substituting it you'd get 200ln20 but if you do it in my form of the equation you get an opposite sign to that of the answers'!

x=−10(v+20ln|v−20|)+C0

=−10(20ln|20|)+C

answers'!x=−10(v+20ln|v−20|)+C0=−10(20ln|20|)+CC=10(20ln|20|)x=−10(v+20ln|v−20|)+200ln20

Here is Your answer ❤ ∫dx=−10∫1+20v−20dvx=−10(v+20ln|v−20|)+Cx+C=−10(v+20ln|v−20|)Sincex+D=−10(v+20ln|v−20|)+E and D−E is an unknown constant, and so is E−D.Anyways, then it's given that when x=0, v=0 so we substitute those in to get the value of the constant.So if you try substituting it you'd get 200ln20 but if you do it in my form of the equation you get an opposite sign to that of the answers'!x=−10(v+20ln|v−20|)+C0=−10(20ln|20|)+CC=10(20ln|20|)x=−10(v+20ln|v−20|)+200ln20or