Question

what is the integration of the following​

Answer 1

Answer:

x tan-1x - ½ ln(1+x2) + C.

Explanation:

So, now we need to integrate tan-1x.

Now to evaluate integration of tan-1x, let u = tan-1x.

Then, du = 1/(1 + x2) dx  

∫ tan-1x dx = ∫ (tan-1x × 1) dx

= x tan-1x – ∫x/1+x2 dx 

= x tan-1x – ½ ∫2x/(1+x2) dx

= x tan-1x - ½ ln ∣1+x2∣ + C

hope you got it

Answer 2

Answer:

it's really very though