What is the interest on ₹ 4500 from January 5 to may 31; 2011 at 8% p.a.?
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Given Principal = Rs 2000, Rate of Interest = 5% per annum and Time = 5 years.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (2000 × 5 × 5)/100
= Rs 500
(ii) Given Principal = Rs 500, Rate of Interest = 12.5% per annum and Time = 4 years.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (500 × 4 × 12.5)/100
= Rs 250
(iii) Given Principal = Rs 4500, Rate of Interest = 4% per annum and Time = 6 months = ½ years
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (4500 × ½ × 4)/100
SI = (4500 × 1 × 4)/100 × 2
= Rs 90
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