Question

what is the IUPAC name of K[BF4] ?

Answer 1

Answer: Potassium tetrafluoroborate

Answer 2

Answer:

The IUPAC name of K[BF₄] will be Potassium tetrafluoridoborate(III).

Explanation:

• In the K[BF₄] , K refers for potassium.
• For the four fluorine ligands, because they are an anionic ligands. We will write tetrafluorido.
• We can show it as ions: K⁺[BF₄]⁻ . So here [BF₄]⁻ is an anionic part of the compound. We will write borate for boron metal.
• Find the oxidation state of boron:  K⁺[BF₄]⁻

            ∴                  $x+4(-1)=-1 \\ x=4-1 \\ x=+3$

Therefore Potassium tetrafluoridoborate(III) is the IUPAC name of the given compound.