Question

What is the IUPAC name of the following alkene?​

Answer 1

Answer:

C

C1

C1 H

C1 H 2

C1 H 2

C1 H 2 =

C1 H 2 = C

C1 H 2 = C2

C1 H 2 = C2 H−

C1 H 2 = C2 H− C

C1 H 2 = C2 H− C3∣

C1 H 2 = C2 H− C3∣ H

C1 H 2 = C2 H− C3∣ HCH

C1 H 2 = C2 H− C3∣ HCH 3

C1 H 2 = C2 H− C3∣ HCH 3

C1 H 2 = C2 H− C3∣ HCH 3

C1 H 2 = C2 H− C3∣ HCH 3 −

C1 H 2 = C2 H− C3∣ HCH 3 − C

C1 H 2 = C2 H− C3∣ HCH 3 − C4

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3 Numbering is done from the end, where the double bond is least numbered.

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3 Numbering is done from the end, where the double bond is least numbered. Hence, it is an alkene. At 3

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3 Numbering is done from the end, where the double bond is least numbered. Hence, it is an alkene. At 3 rd

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3 Numbering is done from the end, where the double bond is least numbered. Hence, it is an alkene. At 3 rd carbon atom one methyl group is present and the longest chain contain 4 carbon atoms.

C1 H 2 = C2 H− C3∣ HCH 3 − C4 H 3 Numbering is done from the end, where the double bond is least numbered. Hence, it is an alkene. At 3 rd carbon atom one methyl group is present and the longest chain contain 4 carbon atoms.Hence, the name is 3-Methylbut-1-ene