Chemistry, asked by sujatasultana239, 11 months ago

What is the IUPAC nane of [Pt(NH3)4Cl2] [PtCl4] ?

Answers

Answered by aryanpunia026

4

Answer:

Explanation:

Tetraaminedichloroplatinum(II) tetrachloroplatinate(IV)

And also, Oxidation state of first is +2 and second is +4.

I hope this helps.

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