Question

what is the k.e of an electron whose d-brogile wavelength is 5000A

Answer 1

Answer:

we have the wavelength associated with the electron. using de- Broglie relation. lambda = h/p ….where p=momentum of electron and h=Planck’s constant. so, p = h/ lambda. the kinetic energy = p^2 /(2m) = (h^2/ lambda^2) . (1/2m) substituting the values of h , m and lambda as given

Explanation:

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