Science, asked by shantimohapatro808, 4 hours ago

What is the KE of a 10g bullet that is fired with a muzzle velocity of 700m/s?

Answers

Answered by haadali
1

Answer:

The K.E. will be equal to 245 Joule

Explanation:

We know that:

  1. Mass of bullet = m = 10gram = 0.001 kilogram
  2. Velocity= 700m/s

Thus, Kinetic Energy can be calculated as:

K.E. = 1/2 mv^2

Putting values:

  • K.E. = 1/2 x (0.001)(700)^2
  • K.E. = 1/2 x (0.001)(490,000)
  • K.E. = 1/2 x (490)
  • K.E. = 245 Joules
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