What is the KE of a 10g bullet that is fired with a muzzle velocity of 700m/s?
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Answer:
The K.E. will be equal to 245 Joule
Explanation:
We know that:
- Mass of bullet = m = 10gram = 0.001 kilogram
- Velocity= 700m/s
Thus, Kinetic Energy can be calculated as:
K.E. = 1/2 mv^2
Putting values:
- K.E. = 1/2 x (0.001)(700)^2
- K.E. = 1/2 x (0.001)(490,000)
- K.E. = 1/2 x (490)
- K.E. = 245 Joules
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