Question

What is the KE of a 1500 kg car going at suburban speed of 14

Answer 1

$\sf \implies K.E =\frac{1}{2}mv { }^{2}$

$\sf \implies \: K.E = \frac{1}{2} \times 1500 \times {14}^{2}$

$\sf \implies \: K.E \: = 147000 \: kg {m}^{2} / {s}^{2}$

$\sf \implies \: K.E= 147 \: kJ$