Question

what is the KE of a 4.5 tonne truck travelling at a speed of 72 km/hr​

Answer 1

Answer:

We know that

$kinetic \: \: energy \: is \: \frac{1}{2}m {v}^{2}$

Here

Mass = 4.5 tonnes = 4500kg

Velocity = 72kmph = 20m/s

Hence K.E=

1/2 × 4500 × 20× 20

. = 900000 JOULES

Answer 2

Answer:

90000 joules

Explanation:

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