Question

What is the KE of a body of mass 10 kg thrown up vertically @ 50m/s. What will be the max

height it will reach ? what will be its velocity at half way mark? What will be its energy at half

way mark? What will be its energy at the maximum height? What is your conclusion? Take g

= 10m/s2​

Answer 1

Step-by-step explanation:

Given :•

mass (m) =10kg

Velocit (v) = 50m/s

gravity (g) = 10m/s

Formula Of kinetic Energy (K•E ) :•

K•E = 1 mv^2

2

= 1 10 × 50

2

= 1 × 5 × 50

= 250

I hope it helps you