Physics, asked by ravneet1946, 11 months ago

what is the KE of a person of mass 55 kg moving with a velocity of 12km per hour​

Answers

Answered by suranatarun
0

Explanation:

KE = ½mv²

KE = ½ x 55 x (12)²

KE. = ½ x 55 x 144

KE. = 55 x 72

KE = 3690 km/h

and in m/s ,

KE = 3690 x 5/ 18

KE = 1025 m/s

Answered by Anonymous
19

\huge\mathfrak{Bonjour!!}

\huge\pink{Solution:-}

Answer:-

⛄ K.E. of the person = 299.475 J.

Step-by-step explanation:-

Given:-

☘ Mass of the person= 55 kg.

☘ Velocity = 12 km/h i.e. 12 × 5/18 = 3.3 m/s

We know that,

K.E. = 1/2 mv²

Now, on substituting the given values in the above mentioned formula, we get,

K.E. = 1/2 × 55 kg × (3.3 m/s)²

=> K.E. = 1/2 × 55 kg × 10.89 m/s ²

=> K.E. = 1/2 × 55 kg × 1089/100 m/s²

=> K.E. = 1/2 × 11 × 1089/20 kg m/s²

=> K.E. = 11979/40 J

=> K.E. of the person = 299.475 J. [Approx.]

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