Question

What is the kinetic energy in joules of a 71kg man running at 5.0 m/s

Answer 1

Answer:

The Formula for KE=1/2 mv^2

Explanation:

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Here,

m=mass=71kg=0.071g (divide by 1000 to get in grams)

v=velocity=5.0m/s

KE=1/2 (0.071)(5)

KE=0.1775 J

Hope it helps  :))

Answer 2

Answer:

Kinetic energy = 1/2 mv^2

= 1/2 × 0.071× 5× 5

= 1/2 × 0.071× 25

= 1/2 × 1.775

= 0.8875 J