Question

what is the kinetic energy of 1 gram of o2 at 57 degrees c

Answer 1

Explanation:

GIVEN:-

=>The mass of O2 is 1g.

=>The temperature is 47°c.

TO FIND:-

=>The kinetic energy.

UNDERSTANDING THE CONCEPT:-

According to the question,

=>The temperature in degree Celsius converted to Kelvin scale,

=>T = 47 + 273

=>T = 230k.

The formula to calculate the number of moles is,

$\sf{n = \dfrac{m}{M} }$

Where,

=>n is number of moles.

=>m is the mass.

=>M is the molar mass.

=>The Molar mass of oxygen o2 is 32g/mol.

According to the kinetic molecular theory of gases, the kinetic energy of n number of moles is given by the equation,

$\sf{K.E = \dfrac{3}{2}nRT }$Where,

=>K.E is the kinetic energy.

=>n is the number of moles.

=>R is the universal gas constant.

=>T is the temperature.

The value of R is 8.314J K-1.

Now, Substituting the values, We get,

$\sf{}K.E = 124.17J$

$\sf{}K.E = 1. 24 \times 10 {}^{2} J$

HENCE PROVED!!