Question

What is the kinetic energy of 1g of O2 at 47 'C

Answer 1

47 degrees C = 320 K

1 g O2 * 1 mol / 32.00 grams = 0.03125 mol O2

Universal gas constant: R = 8.314 J / mol K.

8.314 J / mol K * 0.03125 mol * 320 K = 83.14 J.

This answer assumes that kinetic energy is zero when all the gas particles are infinitely far away from each other and that the gas is an ideal gas.

Answer 2

Answer:

What is the kinetic energy of 1g of O

2

at 47

o

C

Correct option is

A

1.24×10

2

J

Moles of O

2

=

32

1

moles

K. E. of n moles =

2

3nRT

K. E. of

32

1

moles =

2×32

3×1×8.314×320

=1.24×10

2

J

Hence, option A is correct