What is the kinetic energy of a 400 kg horse that is racing around a track at 17 m/s?
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Answer:Kinetic energy = (1/2) (mass) (speed squared)
Kinetic energy = (1/2) (400 kg) (17 m/s)²
Kinetic energy = (1/2) (400 kg) (289 m²/s²)
Kinetic energy = 57,800 Joules
Explanation:
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