Question

What is the L.C.M between 2 and root2?

Answer 1

find the LCM of 2 , √2

2= 1×√2×√2

√2= 1×√2

LCM = 1× √2×√2 =2

LCM of 2 &√2 is 2

Answer 2

Answer:

LCM of the given numbers $\sqrt 2$ and 2 is 2.

To find:

LCM of  the given numbers $\sqrt 2$ and 2  

Solution:

LCM of $\sqrt 2$ and 2 is as under:

We know that the value of 2 is equal to two square roots of 2.

i.e.,

$2=\sqrt2 \times \sqrt 2$

Thus,

LCM of  

$\sqrt 2=\sqrt 2$

$2=\sqrt2 \times \sqrt 2$

Hence, the LCM of the given two numbers will be equal to  

Hence,

L.C.M. $= \sqrt 2\times\sqrt2=2$