Math, asked by bedodyutybanerjee, 1 month ago

what is the L.C.M between (x-1) (x+1)​

Answers

Answered by sivamani162003
1

Answer:

Step-by-step explanation:

Since, L.C.M. * H.C.F. = Product of two numbers

So, L.C.M. of x+1 and x-1 = [(x+1)*(x-1)] / H.C.F. of x+1 and x-1

L.C.M. of x+1 and x-1 = [(x^2) - 1] / H.C.F. of x+1 and x-1

H.C.F. of two numbers is the highest common factor of the numbers. It can also be one.

That is, If x+1 and x-1 have nothing in common then the H.C.F. is one.

L.C.M. of x+1 and x-1 = (x^2) - 1

Answered by sushantkumar25471
1

Answer:

Since, L.C.M. * H.C.F. = Product of two numbers

So, L.C.M. of x+1 and x-1 = [(x+1)*(x-1)] / H.C.F. of x+1 and x-1

L.C.M. of x+1 and x-1 = [(x^2) - 1] / H.C.F. of x+1 and x-1

H.C.F. of two numbers is the highest common factor of the numbers. It can also be one.

That is, If x+1 and x-1 have nothing in common then the H.C.F. is one.

L.C.M. of x+1 and x-1 = (x^2) - 1

Similar questions