What is the largest 4 digit and smallest 3 digit number divisible by 6 15 21 and 24?
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➡HERE IS YOUR ANSWER⬇
Now,
6 = 2 × 3
15 = 5 × 3
21 = 7 × 3
24 = 2 × 2 × 2 × 3
So, lcm = 2 × 2 × 2 × 3 × 5 × 7 = 840.
●)
The largest number in 4 digits = 9999
Now, 9999 = (840 × 11) + 759
So, remainder is = 759
So the largest number, divisible by 6, 15, 21 and 24 is
= 9999 - 759
= 9240.
●)
The smallest number in 3 digits, divisible by 6, 15, 21 and 24 is
= lcm of 6, 15, 21 and 24
= 840.
⬆HOPE THIS HELPS YOU⬅
Now,
6 = 2 × 3
15 = 5 × 3
21 = 7 × 3
24 = 2 × 2 × 2 × 3
So, lcm = 2 × 2 × 2 × 3 × 5 × 7 = 840.
●)
The largest number in 4 digits = 9999
Now, 9999 = (840 × 11) + 759
So, remainder is = 759
So the largest number, divisible by 6, 15, 21 and 24 is
= 9999 - 759
= 9240.
●)
The smallest number in 3 digits, divisible by 6, 15, 21 and 24 is
= lcm of 6, 15, 21 and 24
= 840.
⬆HOPE THIS HELPS YOU⬅
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