What is the largest 4 digit number that is exactly divisible by 93?
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¶ To find Largest n-digit number that is exactly divisible by 'd'
• Consider the largest n-digit No. (say N)
• Divide N by d
• If the remainder obtained after division is 0, then the divided(N) just took is the required No.
• If remainder is not equal to 0, the required No. can be obtained by subtracting remainder 'r' from n-digit No. 'N'
=> Required No. = N - r
Given,
n = 4 => N = 9999
d = 93
Now,
Do 9999 ÷ 93 to know remainder 'r' :
93 | 9999 | 107
……| 930
--------------------------
……|…699 |
……|…651 |
--------------------------
….……(48)
•°• r = 48
•°• Required No. = 9999 - 48 = 9951
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