Math, asked by shreyanvothra, 5 months ago

What is the largest 5-digit number that has no repeating digits and the sum of whose digits is 34?

Answers

Answered by Anonymous
0

Answer:

here is your answer

Step-by-step explanation:

⭐⭐⭐⭐⭐Let the actual number be

(100000a +10000b +1000c+100 d+10e +f)

And according to this problem,

a+b+c+d+e+f = 34

Note that we want the largest number, so I'm taking a =9

So,

b+c+d+e+f = 25

Now, firstly I wanted to take b=9, but digit repetition is not allowed. That's why I take b=8.

Now, c+ d+e+f = 17.

As per the same rule, take c = 7,

Then

d+e+f = 10.

And finally, take d = 6.

Which means that e+f = 4.

Now, what should be the whole values of e and f ? I got them to be :-

e = 2 and f =2,

e= 1 and f =3,

e = 3 and f =1.

Therefore, all the possible numbers are

987613

987622

987631

And as everyone can see, 987631 is the largest one;⭐⭐⭐

Answered by tanviborude
0

Step-by-step explanation:

Let the actual number be

(100000a +10000b +1000c+100 d+10e +f)

And according to this problem,

a+b+c+d+e+f = 34

Note that we want the largest number, so I'm taking a =9

So,

b+c+d+e+f = 25

Now, firstly I wanted to take b=9, but digit repetition is not allowed. That's why I take b=8.

Now, c+ d+e+f = 17.

As per the same rule, take c = 7,

Then

d+e+f = 10.

And finally, take d = 6.

Which means that e+f = 4.

Now, what should be the whole values of e and f ? I got them to be :-

e = 2 and f =2,

e= 1 and f =3,

e = 3 and f =1.

Therefore, all the possible numbers are

987613

987622

987631

as 987631 is the largest number

hope it helps you

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