Question

what is the largest area if Rectangle formed by two perpendicular diamerter and a point if circle of diameter 20/ 2 cm​

Answer 1

HERE IS YOUR ANSWER

Circumference = 39.6 cm

Circumference of a circle = 2πr

⇒39.6 =2×

22

7

×r⇒

39.6×7

2×22

=r⇒r=6.3 cm

Also,

Area of the circle = πr2

=

22

7

×6.3×6.3=124.74 cm2

PLEASE MARK AS BRAINLIEST

Answer 2

Given: diameter of circle is $20\sqrt{2} cm$.

To find: the area of rectangle.

Formula to be used: Area of rectangle = length x breadth.

Step-by-step explanation:

Step 1 of 2

The sides of the rectangle can be calculated by using the Pythagoras theorem.

The radius of the circle will be $\frac{20\sqrt{2} }{2} cm=10\sqrt{2} cm$.

So the side AB will be:

$H^{2} =P^{2} +B^{2} \\\\AB^{2} =(10\sqrt{2} )^{2} +(10\sqrt{2} )^{2} \\\\AB^{2} =200+200\\\\AB^{2} =400\\\\AB=\sqrt{400} \\\\AB=20cm$

Similarly, BC = 20 cm.

Step 2 of 2

Area of ABCD = AB x BC

Area of ABCD = 20 x 20

Area of ABCD = 400 cm2.

The area of the largest rectangle will be 400 cm2.