Math, asked by ashvin, 1 year ago

what is the largest no which when divided with 71 & 126 leaves a remainder 6 & 9 respectively

Answers

Answered by Anonymous

Dividend=quotient * divisor + remainder
d=q71+6
d=a126+9
71q+6=126a+9
This is a way you can solve
but is 71 the divisor or dividend here?please say
ill solve further

Anonymous: Hmmm you're quiet is wrong then

Anonymous: i mean question

ashvin: sorry its divided with 71

Anonymous: Hey do u know what answer u should get?

ashvin: no the site i am refering does not contain the ans

Anonymous: Hmm I'll try

Anonymous: I'm a bit busy right now ashvin will see u later....bye

ashvin: THE QUESTION IS ; The largest number which divides 71 and 126, leaving remainders 6 and 9 respectively is :

Anonymous: Hey ash it is 13

Anonymous: refer mankits answer

Answered by manitkapoor2

71=ax+6
126=ay+9
ax=65,ay=117
65=5x13
117=3x3x13
since both have common factor 13
the largest number which divides is 13
(In otherwords just found hcf)

manitkapoor2: If understand my answer please mark it as best

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