Question

what is the largest number that divides 1206 and 321 leaving remainder 6?

Answer 1

Step-by-step explanation:

let the largest no. be y

• 1206/y=6
• 1206=6y
• y=1206/6
• y=201

similarly

• 321/y=6
• 6y=321
• y=321/6
• y=53.5

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Answer 2

Answer:

15

Step-by-step explanation:

First we need to subtract 6 individually

1206-6 = 1200

321- 6 = 315

Now we need to find the HCF of these two numbers

1200= 2×2×2×2×3×5×5

315= 3×3×5×7

Common factors= 3×5

HCF= 3×5

       =15

Hope this helps you!!