Question

What is the largest number that divides 1206 and 321 leaving remainder 6?
Please explain how to do it.

Answer 1

Answer:

15

Step-by-step explanation:

First deducting the remainder 6 from 1206 and 321 we get

1206–6=1200

321–6=315

Now prime factors of 1200 and 3015 are

1200=2^4*3*5*5

315=3^2*5*7

Thus HCF(1200,315)=3*5=15

Thus 15 is the number which when divides 1206 and 321 then remainder is 6

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Answer 2

Answer:

i hope this answer is helpful