What is the largest number that divides 245 and 1029 leaving remainder 5 in each case?
Answers
Answered by
3
required number=H.C.F OF (245-5) AND (1029-5)
H.C.F. OF 245-5 i.e. 240=2^4 * 3 * 5
H.C.F. OF 1029-5 i.e. 1024=2^10
THEREFORE ,H.C.F OF 1024 AND 240=2 * 2* 2 * 2=16
hence the largest no. that divides 245 and 1029 leaving remainder 5 in each case is 16 .
H.C.F. OF 245-5 i.e. 240=2^4 * 3 * 5
H.C.F. OF 1029-5 i.e. 1024=2^10
THEREFORE ,H.C.F OF 1024 AND 240=2 * 2* 2 * 2=16
hence the largest no. that divides 245 and 1029 leaving remainder 5 in each case is 16 .
Answered by
1
First we have to find the LCM of 245 and 1029.
LCM of 245 and 1029 = 5145. Now we have to add 5 to the LCM of 245 and 1029= 5145+5=5150. The Answer is 5150.
Hope it helps u
Pls Mark it as brainliest
Thanks
Similar questions