What is the largest number that divides 626,3127 and 15628 and leaves remainder 4,5,6 respectively?
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Answered by
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Hey friend !!
Steps to be followed :-
1) Subtract the given remainders from the numbers that are given :-
626 - 1 = 625
3127 - 2 = 3125
15628 - 3 = 15625
2) Find the HCF of 625 , 3125 , 15625 .
15625 = 5 x 5 x 5 x 5 x 5 x 5
3125 = 5 x 5 x 5 x 5 x 5
625 = 5 x 5 x 5 x 5
HCF = 5 x 5 x 5 x 5 = 625
3) 625 is the largest number that divides 626, 3127 and 15628 and leaves remainder of 1,2 and 3 respectively...
Hope it helped you out (^^)^_^(^^)
Steps to be followed :-
1) Subtract the given remainders from the numbers that are given :-
626 - 1 = 625
3127 - 2 = 3125
15628 - 3 = 15625
2) Find the HCF of 625 , 3125 , 15625 .
15625 = 5 x 5 x 5 x 5 x 5 x 5
3125 = 5 x 5 x 5 x 5 x 5
625 = 5 x 5 x 5 x 5
HCF = 5 x 5 x 5 x 5 = 625
3) 625 is the largest number that divides 626, 3127 and 15628 and leaves remainder of 1,2 and 3 respectively...
Hope it helped you out (^^)^_^(^^)
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