Question

what is the largest number that divides 627, 3128, 15629 and leaves remainder 2, 3, 4​

Answer 1

627–2 = 625

3128–3 = 3125

15629–4 = 15625

Now factors of

625 = 5x5x5x5

3125 = 5x5x5x5x5

15625 = 5x5x5x5x5x5

HCF = 5x5x5x5 = 625.

So 625 is the largest number that divides 627, 3128 and 15629 leaving remainders of 2, 3 and 4, respectively.