Question

What is the largest number that will divide 90207, 232585 and 127986 without leaving a remainder?

Answer 1

Solution:

We have to find the HCF of 90207, 232585 and 127986.

90207 = 3 × 3 × 3 × 13 × 257

232585 = 5 × 181 × 257

127986 = 2 × 3 × 83 × 257

Thus, the HCF is 257.

Hence, the largest number that will divide 90207, 232585 and 127986 is 257.