Question

What is the largest voltage you can safely put across a resistor marked 98ohm _0.5watt

Answer 1

Answer:

refer this................ .

Answer 2

Answer:

Maximum power dissipation is rated at 0.5W so I^2R=0.5 . calculate current from this and then resistance times the current gives you the maximum safe voltage.

P = VI

I = V/R

Therefore Power = V * (V/R) = V^2/R

V^2 = P/R

Given Power = 0.5 W

R = 98 Ohms

Therefore V^2 = 0.50/98 = 0.0051

Taking Sq root V = sq root(0.0051)

V = 0.0714 Volts

= 71.4 mV

Hope this helps you

(^_^)